Flight UA 1250: Cleveland → San Francisco
United Airlines4 October 2026LandedUpdated 8 min ago, official airport data
Flight UA 1250, 4 October 2026
All flights Cleveland → San FranciscoLanded
Flight time: 5 h 17 min
Data from the official airport boards. Times are local to each airport.
- Flight time
- 5 h 17 min
- Distance
- ≈ 3,470 km
- Days of the week
Punctuality of flight UA 1250
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
Flight UA 1250: schedule and upcoming dates
- Days it flew in the last 60 days
- Usual departure time
- 09:00
- Usual arrival time
- 11:17
Dates already on the boards
- Sun 4 OctDeparture 09:00, Arrival 11:17Landed
Route of flight UA 1250
Departure airport: Cleveland (CLE). Arrival airport: San Francisco (SFO). Scheduled flight time: about 5 h 17 min. Distance between the airports: about 3,470 km in a straight line.
See also
Questions about flight UA 1250
Is flight UA 1250 on time today?
For 4 October 2026 the airport board shows flight UA 1250 as “Landed”. Departure: Cleveland, 08:52. Arrival: San Francisco, 10:42.
Which terminal and gate does flight UA 1250 use?
Cleveland (CLE): Gate C25. San Francisco (SFO): Terminal 3. Gates are announced shortly before boarding and can change: check the screens at the airport.
How often is flight UA 1250 delayed?
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
How long does flight UA 1250 take?
About 5 h 17 min by the schedule. The airports are 3470 km apart.
On which days does flight UA 1250 operate?
In the last 60 days it was on the boards on: Sunday.