Flight G4 2705: St. Petersburg-Clearwater → Cedar Rapids
Allegiant Air4 October 2026LandedUpdated 6 min ago, official airport data
Flight G4 2705, 4 October 2026
All flights St. Petersburg-Clearwater → Cedar RapidsLanded
Flight time: 2 h 29 min
Data from the official airport boards. Times are local to each airport.
- Flight time
- 2 h 29 min
- Distance
- ≈ 1,756 km
- Days of the week
Punctuality of flight G4 2705
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
Flight G4 2705: schedule and upcoming dates
- Days it flew in the last 60 days
- Usual departure time
- 16:23
- Usual arrival time
- 17:52
Dates already on the boards
- Sun 4 OctDeparture 16:23, Arrival 17:52Landed
Route of flight G4 2705
Departure airport: St. Petersburg-Clearwater (PIE). Arrival airport: Cedar Rapids (CID). Scheduled flight time: about 2 h 29 min. Distance between the airports: about 1,756 km in a straight line.
See also
Questions about flight G4 2705
Is flight G4 2705 on time today?
For 4 October 2026 the airport board shows flight G4 2705 as “Landed”. Departure: St. Petersburg-Clearwater, 16:23. Arrival: Cedar Rapids, 18:10.
Which terminal and gate does flight G4 2705 use?
St. Petersburg-Clearwater (PIE): Gate 4. Gates are announced shortly before boarding and can change: check the screens at the airport.
How often is flight G4 2705 delayed?
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
How long does flight G4 2705 take?
About 2 h 29 min by the schedule. The airports are 1756 km apart.
On which days does flight G4 2705 operate?
In the last 60 days it was on the boards on: Sunday.