Flight G4 237: St. Petersburg-Clearwater → Asheville
Allegiant Air4 October 2026LandedUpdated 25 min ago, official airport data
Flight G4 237, 4 October 2026
All flights St. Petersburg-Clearwater → AshevilleLanded
Flight time: 1 h 46 min
Data from the official airport boards. Times are local to each airport.
- Flight time
- 1 h 46 min
- Distance
- ≈ 837 km
- Days of the week
Punctuality of flight G4 237
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
Flight G4 237: schedule and upcoming dates
- Days it flew in the last 60 days
- Usual departure time
- 13:14
- Usual arrival time
- 15:00
Dates already on the boards
- Sun 4 OctDeparture 13:14, Arrival 15:00Landed
Route of flight G4 237
Departure airport: St. Petersburg-Clearwater (PIE). Arrival airport: Asheville (AVL). Scheduled flight time: about 1 h 46 min. Distance between the airports: about 837 km in a straight line.
See also
Questions about flight G4 237
Is flight G4 237 on time today?
For 4 October 2026 the airport board shows flight G4 237 as “Landed”. Departure: St. Petersburg-Clearwater, 13:14. Arrival: Asheville, 14:51.
Which terminal and gate does flight G4 237 use?
St. Petersburg-Clearwater (PIE): Gate 10. Gates are announced shortly before boarding and can change: check the screens at the airport.
How often is flight G4 237 delayed?
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
How long does flight G4 237 take?
About 1 h 46 min by the schedule. The airports are 837 km apart.
On which days does flight G4 237 operate?
In the last 60 days it was on the boards on: Sunday.