Flight G4 1058: Evansville → St. Petersburg-Clearwater
Allegiant Air4 October 2026LandedUpdated 48 min ago, official airport data
Flight G4 1058, 4 October 2026
All flights Evansville → St. Petersburg-ClearwaterLanded
Flight time: 1 h 30 min
Data from the official airport boards. Times are local to each airport.
- Flight time
- 1 h 30 min
- Distance
- ≈ 1,213 km
- Days of the week
Punctuality of flight G4 1058
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
Flight G4 1058: schedule and upcoming dates
- Days it flew in the last 60 days
- Usual departure time
- 13:22
- Usual arrival time
- 15:52
Dates already on the boards
- Sun 4 OctDeparture 13:22, Arrival 15:52Landed
Route of flight G4 1058
Departure airport: Evansville (EVV). Arrival airport: St. Petersburg-Clearwater (PIE). Scheduled flight time: about 1 h 30 min. Distance between the airports: about 1,213 km in a straight line.
See also
Questions about flight G4 1058
Is flight G4 1058 on time today?
For 4 October 2026 the airport board shows flight G4 1058 as “Landed”. Departure: Evansville, 13:22. Arrival: St. Petersburg-Clearwater, 15:52.
Which terminal and gate does flight G4 1058 use?
Evansville (EVV): Gate B4. Gates are announced shortly before boarding and can change: check the screens at the airport.
How often is flight G4 1058 delayed?
The last 60 days of boards hold fewer than 5 finished flights with a known departure time: too few to count punctuality.
How long does flight G4 1058 take?
About 1 h 30 min by the schedule. The airports are 1213 km apart.
On which days does flight G4 1058 operate?
In the last 60 days it was on the boards on: Sunday.